'0x0.0p0' thus, negative zero produces the result

If m is zero, it is represented by the string.

Result 'Infinity' and negative infinity produces 'Infinity' thus, positive infinity produces the

If m is infinity, it is represented by the string.

( '-') if the sign is positive, no signĬharacter appears in the result.

Otherwise, the result is a string that represents the signĪnd magnitude of the argument.

Returns a hexadecimal string representation of theĭouble argument.

toHexString public static String toHexString(double d).

Returns: a string representation of the argument. Parameters: d - the double to be converted. To create localized string representations of a floating-point Significant bit of the significand of d must be 0. To x, then d must be one of them and the least To x or if two double values are equally close Representation produced by this method for a finite nonzero argumentĭ. X is the exact mathematical value represented by the decimal The fractional part, and beyond that as many, but only as many, moreĭigits as are needed to uniquely distinguish the argument value fromĪdjacent values of type double. M or a? There must be at least one digit to represent How many digits must be printed for the fractional part of Produced by the method Integer.toString(int). Representing the fractional part of a, followed by theīy a representation of n as a decimal integer, as Magnitude is then represented as the integer part of a,Īs a single decimal digit, followed by '. 'computerized scientific notation.' Let n be the unique

If m is less than 10 -3 or greater than orĮqual to 10 7, then it is represented in so-called.

More decimal digits representing the fractional part of m. M, in decimal form with no leading zeroes, followed by Than 10 7, then it is represented as the integer part of

If m is greater than or equal to 10 -3 but less.

'-0.0' and positive zero produces the result '0.0' thus, negative zero produces the result

If m is zero, it is represented by the characters.

'Infinity' and negative infinity produces the result 'Infinity' thus, positive infinity produces the result

If m is infinity, it is represented by the characters.

( '-') if the sign is positive, no sign characterĪppears in the result. The first character of the result is ' -' Magnitude (absolute value) of the argument.

Otherwise, the result is a string that represents the sign and.If the argument is NaN, the result is the string.All characters mentioned below are ASCII characters.

Returns a string representation of the doubleĪrgument.

Double infinity box